Задание
По известному частному восстановить процесс деления в столбик (вписать пропущенные числа):
| \(\displaystyle 4\) | \(\displaystyle 6\) | \(\displaystyle 3\) | \(\displaystyle 3\) | \(\displaystyle 2\) | \(\displaystyle 3\) | \(\displaystyle 5\) | \(\displaystyle 1\) | |
| \(\displaystyle –\) | ||||||||
| \(\displaystyle 1\) | \(\displaystyle 3\) | \(\displaystyle 2\) | ||||||
| \(\displaystyle –\) | ||||||||
| \(\displaystyle –\) | ||||||||
| \(\displaystyle 0\) |
Решение
1. Умножим \(\displaystyle 351\) на \(\displaystyle 1{\small:}\)
\(\displaystyle 351=351 \cdot {\bf 1}{\small.}\)
| \(\displaystyle 4\) | \(\displaystyle 6\) | \(\displaystyle 3\) | \(\displaystyle 3\) | \(\displaystyle 2\) | \(\displaystyle 3\) | \(\displaystyle 5\) | \(\displaystyle 1\) | |
| \(\displaystyle –\) | ||||||||
| \(\displaystyle \bf 3\) | \(\displaystyle \bf 5\) | \(\displaystyle \bf 1\) | \(\displaystyle \bf 1\) | \(\displaystyle 3\) | \(\displaystyle 2\) | |||
| \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | |||||
| \(\displaystyle –\) | ||||||||
| \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | |||||
| \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | ||||||
| \(\displaystyle –\) | ||||||||
| \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | ||||||
| \(\displaystyle 0\) |
2. Вычитаем:
\(\displaystyle 463-351={\bf 112}{\small.}\)
| \(\displaystyle 4\) | \(\displaystyle 6\) | \(\displaystyle 3\) | \(\displaystyle 3\) | \(\displaystyle 2\) | \(\displaystyle 3\) | \(\displaystyle 5\) | \(\displaystyle 1\) | |
| \(\displaystyle –\) | ||||||||
| \(\displaystyle 3\) | \(\displaystyle 5\) | \(\displaystyle 1\) | \(\displaystyle 1\) | \(\displaystyle 3\) | \(\displaystyle 2\) | |||
| \(\displaystyle \bf 1\) | \(\displaystyle \bf 1\) | \(\displaystyle \bf 2\) | \(\displaystyle {\small?}\) | |||||
| \(\displaystyle –\) | ||||||||
| \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | |||||
| \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | ||||||
| \(\displaystyle –\) | ||||||||
| \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | ||||||
| \(\displaystyle 0\) |
Сносим десятки числа \(\displaystyle 463{\bf 3}2\) (это цифра \(\displaystyle 3{\small:}\))
| \(\displaystyle 4\) | \(\displaystyle 6\) | \(\displaystyle 3\) | \(\displaystyle \bf 3\) | \(\displaystyle 2\) | \(\displaystyle 3\) | \(\displaystyle 5\) | \(\displaystyle 1\) | |
| \(\displaystyle –\) | ||||||||
| \(\displaystyle 3\) | \(\displaystyle 5\) | \(\displaystyle 1\) | \(\displaystyle 1\) | \(\displaystyle 3\) | \(\displaystyle 2\) | |||
| \(\displaystyle 1\) | \(\displaystyle 1\) | \(\displaystyle 2\) | \(\displaystyle \bf 3\) | |||||
| \(\displaystyle –\) | ||||||||
| \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | |||||
| \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | ||||||
| \(\displaystyle –\) | ||||||||
| \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | ||||||
| \(\displaystyle 0\) |
3. Умножаем \(\displaystyle 351\) на \(\displaystyle 3{\small:}\)
\(\displaystyle 1053=351 \cdot {\bf 3}{\small.}\)
| \(\displaystyle 4\) | \(\displaystyle 6\) | \(\displaystyle 3\) | \(\displaystyle 3\) | \(\displaystyle 2\) | \(\displaystyle 3\) | \(\displaystyle 5\) | \(\displaystyle 1\) | |
| \(\displaystyle –\) | ||||||||
| \(\displaystyle 3\) | \(\displaystyle 5\) | \(\displaystyle 1\) | \(\displaystyle 1\) | \(\displaystyle \bf 3\) | \(\displaystyle 2\) | |||
| \(\displaystyle 1\) | \(\displaystyle 1\) | \(\displaystyle 2\) | \(\displaystyle 3\) | |||||
| \(\displaystyle –\) | ||||||||
| \(\displaystyle \bf 1\) | \(\displaystyle \bf 0\) | \(\displaystyle \bf 5\) | \(\displaystyle \bf 3\) | |||||
| \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | ||||||
| \(\displaystyle –\) | ||||||||
| \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | ||||||
| \(\displaystyle 0\) |
4. Вычитаем:
\(\displaystyle 1123-1053={\bf 70}{\small.}\)
| \(\displaystyle 4\) | \(\displaystyle 6\) | \(\displaystyle 3\) | \(\displaystyle 3\) | \(\displaystyle 2\) | \(\displaystyle 3\) | \(\displaystyle 5\) | \(\displaystyle 1\) | |
| \(\displaystyle –\) | ||||||||
| \(\displaystyle 3\) | \(\displaystyle 5\) | \(\displaystyle 1\) | \(\displaystyle 1\) | \(\displaystyle 3\) | \(\displaystyle 2\) | |||
| \(\displaystyle 1\) | \(\displaystyle 1\) | \(\displaystyle 2\) | \(\displaystyle 3\) | |||||
| \(\displaystyle –\) | ||||||||
| \(\displaystyle 1\) | \(\displaystyle 0\) | \(\displaystyle 5\) | \(\displaystyle 3\) | |||||
| \(\displaystyle \bf 7\) | \(\displaystyle \bf 0\) | \(\displaystyle {\small?}\) | ||||||
| \(\displaystyle –\) | ||||||||
| \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | ||||||
| \(\displaystyle 0\) |
Сносим единицы числа \(\displaystyle 4633{\bf 2}\) (это цифра \(\displaystyle 2{\small:}\))
| \(\displaystyle 4\) | \(\displaystyle 6\) | \(\displaystyle 3\) | \(\displaystyle 3\) | \(\displaystyle \bf 2\) | \(\displaystyle 3\) | \(\displaystyle 5\) | \(\displaystyle 1\) | |
| \(\displaystyle –\) | ||||||||
| \(\displaystyle 3\) | \(\displaystyle 5\) | \(\displaystyle 1\) | \(\displaystyle 1\) | \(\displaystyle 3\) | \(\displaystyle 2\) | |||
| \(\displaystyle 1\) | \(\displaystyle 1\) | \(\displaystyle 2\) | \(\displaystyle 3\) | |||||
| \(\displaystyle –\) | ||||||||
| \(\displaystyle 1\) | \(\displaystyle 0\) | \(\displaystyle 5\) | \(\displaystyle 3\) | |||||
| \(\displaystyle 7\) | \(\displaystyle 0\) | \(\displaystyle \bf 2\) | ||||||
| \(\displaystyle –\) | ||||||||
| \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | ||||||
| \(\displaystyle 0\) |
5. Умножаем \(\displaystyle 351\) на \(\displaystyle 2{\small:}\)
\(\displaystyle 702=351 \cdot {\bf 2}.\)
| \(\displaystyle 4\) | \(\displaystyle 6\) | \(\displaystyle 3\) | \(\displaystyle 3\) | \(\displaystyle 2\) | \(\displaystyle 3\) | \(\displaystyle 5\) | \(\displaystyle 1\) | |
| \(\displaystyle –\) | ||||||||
| \(\displaystyle 3\) | \(\displaystyle 5\) | \(\displaystyle 1\) | \(\displaystyle 1\) | \(\displaystyle 3\) | \(\displaystyle \bf 2\) | |||
| \(\displaystyle 1\) | \(\displaystyle 1\) | \(\displaystyle 2\) | \(\displaystyle 3\) | |||||
| \(\displaystyle –\) | ||||||||
| \(\displaystyle 1\) | \(\displaystyle 0\) | \(\displaystyle 5\) | \(\displaystyle 3\) | |||||
| \(\displaystyle 7\) | \(\displaystyle 0\) | \(\displaystyle 2\) | ||||||
| \(\displaystyle –\) | ||||||||
| \(\displaystyle \bf 7\) | \(\displaystyle \bf 0\) | \(\displaystyle \bf 2\) | ||||||
| \(\displaystyle 0\) |
Таким образом, мы восстановили весь процесс деления в столбик.