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Теория: Умножение двузначных чисел

Задание

Перемножить числа:

  \(\displaystyle 2\)\(\displaystyle 3\)
 \(\displaystyle \times\)  
  \(\displaystyle 3\)\(\displaystyle 2\)
 
  
\(\displaystyle +\)   
  
 
 

 

Решение

1. Умножаем единицы числа \(\displaystyle 3\underline{2} \) (это цифра \(\displaystyle 2 \)) на число \(\displaystyle 23{\small:}\)

 

\(\displaystyle 2 \cdot 23=46{\small.} \)

 

  \(\displaystyle \bf2\)\(\displaystyle \bf3\)
 \(\displaystyle \times\)  
  \(\displaystyle 3\)\(\displaystyle \bf2\)
 
  \(\displaystyle \bf4\)\(\displaystyle \bf6\)
\(\displaystyle +\)   
 \(\displaystyle ?\)\(\displaystyle ?\) 
 
 \(\displaystyle ?\)\(\displaystyle ?\)\(\displaystyle ?\)

 

2. Умножаем десятки числа \(\displaystyle \underline{3}2 \) (это цифра \(\displaystyle 3 \)) на число \(\displaystyle 23{\small:}\)

 

\(\displaystyle 3 \cdot 23=69 {\small.}\)

 

  \(\displaystyle \bf2\)\(\displaystyle \bf3\)
 \(\displaystyle \times\)  
  \(\displaystyle \bf3\)\(\displaystyle 2\)
 
  \(\displaystyle 4\)\(\displaystyle 6\)
\(\displaystyle +\)   
 \(\displaystyle \bf6\)\(\displaystyle \bf9\) 
 
 \(\displaystyle ?\)\(\displaystyle ?\)\(\displaystyle ?\)

 

3. Складываем числа:

  \(\displaystyle 4\)\(\displaystyle 6\)
\(\displaystyle +\)   
 \(\displaystyle 6\)\(\displaystyle 9\) 
 
 \(\displaystyle 7\)\(\displaystyle 3\)\(\displaystyle 6\)

 

В итоге мы получаем:

  \(\displaystyle 2\)\(\displaystyle 3\)
 \(\displaystyle \times\)  
  \(\displaystyle 3\)\(\displaystyle 2\)
 
  \(\displaystyle 4\)\(\displaystyle 6\)
\(\displaystyle +\)   
 \(\displaystyle 6\)\(\displaystyle 9\) 
 
 \(\displaystyle 7\)\(\displaystyle 3\)\(\displaystyle 6\)

Ответ: \(\displaystyle 736{\small.}\)